19y-y^2+70=0

Solution for 19y-y^2+70=0 equation:

19y-y^2+70=0

We add all the numbers together, and all the variables

-1y^2+19y+70=0

a = -1; b = 19; c = +70;
Δ = b2-4ac
Δ = 192-4·(-1)·70
Δ = 641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{641}}{2*-1}=\frac{-19-\sqrt{641}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{641}}{2*-1}=\frac{-19+\sqrt{641}}{-2}
$